# Python asserts

All

### Intro

I was doing some python tests recently I came to use python asserts again, np_asserts, python asserts and unittest framework. All very very useful, but I think the original assert is so clever and easy to use, we should apply them in everyday life.

### asserts

I was comparing the name of a bank (string) with the calculated value of a function that returns it.
assert get_from_id_name_bank(‘004’) == ‘TD’
Similar to the example in 

### np library

Np is also so straightforward, just need to do import numpy as np and it’s done! Put the comparison, and done!

Comparing arrays for example:

np.testing.assert_array_equal(expected,banks)
All the supported functions are here .

### unittest

That’s a complete framework for testing and it’s very simple and has set_up, and tear_down. All in it.

`    python -m unittest -v test_module`

You can add some verbosity via v while doing the execution

### Source

https://github.com/FranciscoMeloJr/Python-Tests/tree/master/

### REFs

https://code-maven.com/slides/python-programming/pytest-compare-strings

https://docs.scipy.org/doc/numpy-1.13.0/reference/routines.testing.html

 https://docs.python.org/3/library/unittest.html (for python 3)

# Little python exercise

All

### Intro

Recently I did an interview with the following problem:

You have a list of strings, on our list, some of the strings were corrupted on the reading process. You want to avoid duplications so do an algorithm to solve this.

List example: ttoo, toto, oott.

Example output: toto.

List example 2:  xt, tx.

Example output 2: xt.

### Solutions

There are several ways to solve the problem and basically, you can understand it as a sort algorithm, a kind of special sort, but a sort. Therefore a bubble sort or insertion sort can be applied.

#### Solution 1

My second solution was to come back to a dict and try to use it to optimize the size comparison. However, since I’m using a dict (i.e. an encoding operation) I will need therefore an operation for translate it in a list (i.e. decoding operation).

Part A – encoding:

```for each_word in words:
key = len(each_word)
if key not in result:
result[key] = [each_word]
else:
list_values = result[key]
list_values.append(each_word)
result[key] = list_values```

Part A2: I use an aux function to end correctly in the dict

```def create_new_list(list_values):
#['ot', 'to', 'tt']
#['to', 'tt']
sorted(list_values)

list_new = [list_values]
flag = True
for i in range(1, len(list_values)):
flag = True
for each in list_new:
if set(list_values[i]) == set(each):
flag = False
if flag:
list_new.append(list_values[i])
return list_new```

#### Solution 2

This was actually my first solution on the head, but second to be implemented. And its more or less based on the insertion sort algorithm and basically inserts an element on the final list if and only if the set of this element not there.  [I mean based on insertion because you will get the elements on the list and compare with the final list.] + the survival flag for each element.

However, you still need to do the size comparison to avoid tt in ttoo problems:

```flag = True
for i in range(1, len(words)):
flag = True
for each in final:
if len(words[i]) == len(each) and set(words[i]) == set(each):
flag = False
if flag:
final.append(words[i])
return final```

The solution can be improved by using the sorted using len option (i) + the comparison is first done on the length and then on the set, avoiding unnecessary comparisons.

``(i) sorted(xs, key=len)``

#### Solution 3

Solution 3 would use a dict comprehension on the first solution. But after thinking about it, it just too noisy and unclear for the reader.

(i) I’m creating the values of the Dict on the fly, so I don’t need an extra function to do it for me (encoding).

(ii) I just put a list comprehension in the end (for the decoder operation).

```(i)for each_word in words:
key = len(each_word)
if key not in result:
result[key] = [each_word]
else:
list_values = result[key]
# 2:[cra] - car
for each in list_values:
if set(each) != set(each_word):
list_values.append(each_word)
result[key] = list_values```
`(ii) return [result.get(each_key) for each_key in result.keys()]`

#### Solution 4

It’s totally possible to do it in just one list comprehension, though it would be very long though, basically because one would need to condense the survival code within the list comprehension. I don’t think it worth though.

### Source

All the solutions are there.

https://github.com/FranciscoMeloJr/Python-Tests/tree/master/banks

# Reward System Studies of Video-Game Playing / Neuroscience study

All

### Intro

At SMU, back in Halifax, I studied Video-games and neuroscience doing a small EEG experiment in the end. The experiment was not conclusive therefore it was not published.

### Content

The full content can be found here , which is a report for the class in Cognitive Neuroscience 1, from Prof Jason Ivanoff.

### Abstract

This review covers several studies that have measured the influence of games through
the functional Magnetic Resonance Interference – fMRI – method as a key in the effort to
understand cognitive act of game play. The reward system is the key for the understanding of videogame play, so after explaining it several studies are summarized in details with the highlights and main concepts preserved for the understanding of the current relations with games. The activations areas vmPFC, dorsal striatum, dorsal parts of the ACC, rTP, striatum, midbrain (including VTA/SN) and ventral visual stream. Moreover, several of the deactivations areas during game play are discussed: OFC, caudate nucleus, putamen and nucleus accumbens, NAc that can be very important in a cognitive perspective. Also the lack of emphasis in the NAc which plays an key role in reward system and in the impulsivity and aggression is discussed. It will also discuss tendencies considering the limitations reveled.
Keywords: fMRI, Video-Game, FPS, Reward System

# DevOps Summary

All

### Intro

While study here at home, I tried to summarize several concepts and tools for DevOps.

### Reviews

I did the review in Portuguese actually, sorry.

REFs

There are several, I put them all in one place, at the End.